STAT Statistics Project Example | Topics and Well Written Essays - 1250 words

STAT - Statistics Project ExampleFrom these results we reject the null surmise that the average hotel price in Philadelphia is $129.50 since we have proven that the average hotel room at Philadelphia is significantly disparate from $125 hence its not $ 129.50.Sample size = 250 and they believed that the average is 75%. It means that the confidence breakup is at = 0.25. We calculate the sample mean as xbar= 250/168 = 1.488 and that the claimed average =0.75 thus t = 1.48-0.75)/Since the resultant Z statistic test is less(prenominal) than the obtained respect of (168/250) = 0.672, we reject the null hypothesis that there proportion of drivers under act upon of alcoholic drink are significantly less than 75%. We conclude that the proportion of drivers under the influence of alcohol is not less than 75%.Z = Sample mean- 0/ /n = 9-6 2.47/100 = 12.146. The critical value of Z is obtained from the tables as Z /2 = Z 0.05 /2 = Z 0.025 = 1.96. but since the assumed is greater than th e test statistic, we reject the null hypothesis that the mean waiting time will be 6 minutes or that its not true that the average waiting time will be cut from the current 9- 10 minute.Let us find out the critical value of chi-squared (2) = (n-1) s2 2 = (25-1)0.4 /0.3 = 32. This is the obtained chi-square and from the chi-square tables, we generalise the value of the critical region as 36.42 (Bowman par 3). Since its a left- tailed test, our rejection region is less than 36.42 i.e. (2